89.9k views
1 vote
You are asked to build an LC circuit that oscillates at 13 kHz. In addition, you are told that the maximum current in the circuit can be 0.14 A and the maximum energy stored in the capacitor must be 1.4x10-5 J. What value of inductor and capacitor should you choose

1 Answer

3 votes

Answer:

a)
L=0.00142H

b)
C=2.65*10^(-12)

Step-by-step explanation:

From the question we are told that:

Frequency
F=13kHz

Current
I=0.14A

Capacitor
C_e=1.4*10^(-5)J

Generally the equation for Energy in the inductor is mathematically given by

Where L is now subject


L=(2C_e)/(I^2)


L=(2*1.4*10^(-5))/((0.14)^2)


L=0.00142H

Generally the equation for Value of Capacitor is mathematically given by


C=(1)/((2 \pi f)^2) L


C=(1)/((2 3.142 13*10^3Hz)^2) *0.00142


C=2.65*10^(-12)

User John Colanduoni
by
6.8k points