Question

What are the zeros of the following quadratic equation: y = 6x2 - 17x - 3

Answer 1

`\displaystyle x=-(1)/(6), 3`

Explanation:

Hi there!

`y = 6x^2 - 17x - 3`

Factor by grouping:

`y = 6x^2 - 18x+1x - 3\\y = 6x(x- 3)+1x - 3\\y = 6x(x- 3)+(x - 3)\\y = (6x+1)(x- 3)`

Let y=0. Apply the zero product property:

`0 = (6x+1)(x- 3)`

`6x+1=0\\6x=-1\\\\\displaystyle x=-(1)/(6)`

AND

`x-3=0\\x=3`

I hope this helps!