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Answer:
Follow:
- The potential energy (P.E) at the top is 392 J.
- The kinetic energy (K.E) at the top is 0 J.
- The potential energy (P.E) at the halfway point is 196 J.
- The kinetic energy (K.E) at the halfway point is 196 J.
Step-by-step explanation:
Facts - Key Details Given:
- mass of the rock: m = 2 kg
- height of the cliff: h = 20 m
- speed of the rock at the halfway point: v = 14 m/s
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Calculations:
#1: The potential energy (P.E) and kinetic energy (K.E) when its at the top;
P.E = mgh
P.E = (2)(9.8)(20)
P.E= 392 J
K.E = ¹/₂mv²
where;
v is velocity of the rock at the top of the cliff = 0
K.E = ¹/₂(2)(0)²
K.E = 0
#2: The potential energy (P.E) and kinetic energy (K.E) at the halfway point;
P.E = mg(¹/₂h)
P.E = (2)(9.8)(¹/₂ x 20)
P.E = 196 J
K.E = ¹/₂mv²
where;
v is velocity of the rock at the halfway point = 14 m/s
K.E = ¹/₂(2)(14)²
K.E = 196 J.