Question

Find the equation of a line perpendicular to 2x + 4y = -8 that passes through the

point (-4,4).

Answer 1

2y-×+12=0

Explanation:

ıf two lisesi are perpendicular to each other the product of their slope is -1 2×+y = -8 y=-2×-8 m =-2 m×-2=-1 m = -1/-2 =1/2 equtaion of a straight line with a known point a slope ( y - y1) = m (×-×1) later ( y+4) = 1/2 (×-4) later 2y+8 =×-4 2y -×+12=0 my english is bad i hope it was helpful