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In ∆ ABC,AD is the altitude from A to BC .Angle B is 48°,angle C is 52° and BC is 12,8 cm. Determine the length of AD

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Answer:

7,6 cm

Explanation:

The law of sines can be used to find the length AB.

AB/sin(C) = BC/sin(A)

A = 180° -48° -52° = 80°

AB = BC·sin(C)/sin(A) = 12,8·sin(52°)/sin(80°)

The sine function can be used to find AD from AB.

AD/AB = sin(48°)

AD = AB·sin(48°) = 12,8·sin(48°)sin(52°)/sin(80°)

AD ≈ 7,61 cm

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The dimension of interest is ha in the attachment, the height from vertex A.

In ∆ ABC,AD is the altitude from A to BC .Angle B is 48°,angle C is 52° and BC is-example-1
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