Question

If the ring rolls (without slipping) all the way to point 2, what is the ring's energy at point 2 in terms of h2 and v2?

Answer 1

Following are the response to the given question:

Step-by-step explanation:

`F_2=mgh_2+(1)/(2)mv_2^2+(1)/(2)mR^2(W)^2\\\\\therefore \\\\ \to WR=v_2\\\\E_2=Mgh_2+MV_2^2`