Question

The graph of a line is shown below. What is the equation of the line, in slope-intercept form, that is parallel to this line and has a y-intercept of 1?

Answer 1

`y = - (3)/(2) x + 1`

Explanation:

Slope -intercept form: y= mx +c, where m is the slope and c is the y-intercept.

Parallel lines have the same slope. Let's find the slope of the given line.

Given points: (-2, 0) and (0, -3)

`\boxed{slope = (y1 - y2)/(x1 - x2) }`

slope of given line

`= (0 - ( - 3))/( - 2 - 0)`

`= (0 + 3)/( - 2)`

`= - (3)/(2)`

`y = - (3)/(2) x + c`

Given that the y- intercept is 1, c= 1.

`y = - (3)/(2) x + 1`