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What is the x-intercept of the graph of the function f(x) = x2 − 16x + 64?

(−8, 0)
(0, 8)
(8, 0)
(0, −8)

User Blood
by
3.5k points

2 Answers

6 votes

Answer:

8,0

edge 20201

User Nathan Kinsinger
by
3.3k points
4 votes

Answer:

(8,0)

Explanation:

f(x) = x^2 − 16x + 64

The x intercepts ( or zeros) are found by setting y=0

0 = x^2 − 16x + 64

Factor

0 = (x-8)(x-8)

Using the zero product property

x-8 =0 x-8 =0

x=8 x=8

(8,0)

User Talbot
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3.8k points