Complete Question
According to a study done by a university student, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267 Suppose you sit on a bench in a mall and observe people's habits as they sneeze
(a) What is the probability that among 18 randomly observed individuals exactly 6 do not cover their mouth when sneezing?
Answer:

Explanation:
From the question we are told that:
Sample size

Probability

No. that do not cover their mouth when sneezing

Generally the equation for The Binomial distribution is mathematically given by
Parameters
B(18,0.267)
Therefore

Where

Therefore

