Question

Sarah is going from home to school then to the library to study and finally to the part to meet with friends before going home. Find the distance Sarah will travel today based on the locations of each stop on the coordinate plane. Include:

Distances between all 4 locations
Total distance
The method used for each calculation

Sarah’s house (2,-5)
The school (2,4)
Library (-3,4)
Park (-3,-5)

Answer 1

i) The distance between Sarah's house and the school is 9

ii) The distance between the school and the library is 5

iii) The distance between the library and the park is 9

iv) The distance between the park and Sarah's house is 5

2) The total distance Sarah travels is 28

Explanation:

The given coordinates of the locations are;

Sarah's house (2, -5)

The school (2, 4)

Library (-3, 4)

Park (-3, -5)

Sarah's journey is; From the house → The school → Library → Park → House

The distance, d, between two coordinate points, (x₁, y₁) and (x₂, y₂) is given as follows;

d =
`\sqrt{\left (y_(2)-y_(1) \right )^(2)+\left (x_(2)-x_(1) \right )^(2)}`

i) Therefore, the distance between Sarah's house ((x₁, y₁) = (2, -5)) and the school ((x₂, y₂) = (2, 4)), d₁, is d₁ = √((2 - 2)² + (4 - (-5))²) = 9

Sarah's house → The school = 9

ii) The distance between the school ((x₁, y₁) = (2, 4)), and the library, ((x₂, y₂) = (-3, 4)), d₂ = √((-3 - 2)² + (4 - 4)²) = 5

The school → Library = 5

iii) The distance between the library ((x₁, y₁) = (-3, 4)), and the park ((x₂, y₂) = (-3, -5)), d₃ = √((-3 - (-3))² + (-5 - 4)²) = 9

The library → The park = 9

iv) The distance between the park ((x₁, y₁) = (-3, -5)), and Sarah's house ((x₂, y₂) = (2, -5)), d₃ = √((2 - (-3))² + (-5 - (-5))²) = 5

The park → Sarah's house → 5

2) The total distance = 9 + 5 + 9 + 5 = 28.