Complete Question
A parallel plate capacitor creates a uniform electric field of 5 x 10^4 N/C and its plates are separated by 2 x 10^{-3}'m. A proton is placed at rest next to the positive plate and then released and moves toward the negative plate. When the proton arrives at the negative plate, what is its speed?
Answer:

Step-by-step explanation:
From the question we are told that:
Electric field

Distance

At negative plate
Generally the equation for Velocity is mathematically given by

Therefore



