Question

`\sqrt{4+\sqrt{4+\sqrt{4+...+√(4)`

Answer 1

y=0.5+sqrt(17)

Explanation:

Let y=sqrt{4+sqrt{4+...+sqrt(4)}

y=sqrt(4+y). (Since it's an infinite series)

y^2=4+y, y=0.5-sqrt(17) or 0.5+sqrt(17). We will omit the negative since root values are positive.