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Help with math it would help with summer school

Help with math it would help with summer school-example-1
User Snapshoe
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1 Answer

5 votes

Answer:


A). \ \ ((72\pi + 9\pi ))/(4) \ in^2

Explanation:

Given;

radius of the circle, r = 9 inches

the part of the circle cut out = one-forth of the complete circle

the angle of the sector cut out θ= ¹/₄ x 360 = 90⁰

Area of the complete circle = πr² = π x 9² = 81π in²

Area of the sector cut out =
= (\theta )/(360) \pi r^2 = (90)/(360) \pi (9^2) = (1)/(4) * 81\pi = (81 \pi)/(4) = ((72\pi + 9\pi))/(4) \ in^2

Therefore, the only correct option is A.
((72\pi + 9\pi ))/(4) \ in^2

User Kaluva
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