Question

Calculate the molarity of a solution consisting of 65.5 g of K2S0 4 in 5.00 L of solution. ​

Answer 1

Molarity is 0.075 M.

Step-by-step explanation:

Moles:

`{ \tt{ = (65.5)/(RFM) }}`

RFM of potassium sulphate :

`{ \tt{ = (39 * 2) + 32 + (16 * 4)}} \\ = 174 \: g`

substitute:

`{ \tt{moles = (65.5)/(174) = 0.376 \: moles}}`

In volume of 5.00 l:

`{ \tt{5.00 \: l = 0.376 \: moles}} \\ { \tt{1 \: l = ( (0.376)/(5.00) ) \: moles}} \\ { \tt{molarity = 0.075 \: mol \: l {}^( - 1) }}`