Question

A bedroom that measures 11 ft by 12 ft by 8.0 ft contains 35.41 kg of air at 25 C. What is the pressure of the air in the room? You may assume that the molar mass of air is 29.0 g/mole.

Answer 1

9.97×10⁻⁴ atm

Step-by-step explanation:

Applying,

PV = nRT............... Equation 1

Where P = pressure, V = volume, n = number of moles of air, R = molar gas constant, T = Temperature.

make P the subject of the equation

P = nRT/V............ Equation 2

From the question,

Given: V = (11×12×8) ft³ = 1056 ft³ = (1056×28.3168) = 29902.5 L, T = 25°C = (25+273) = 298 K, n = 35.41/29 = 1.22 mole

Constant: R = 0.082 atm.L/K.mol

Substitute these values into equation 2

P = 1.22×0.082×298/29902.5

P = 9.97×10⁻⁴ atm