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Write the point-slope form of an equation of the line through the points (-4, 7) and (5, 3).

User Fjordo
by
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1 Answer

3 votes

Answer:


y-7=-(\displaystyle 4)/(\displaystyle 9)(x+4)

OR


y-3=-(\displaystyle 4)/(\displaystyle 9)(x-5)

Explanation:

Hi there!

Point-slope form:
y-y_1=m(x-x_1) where
m is the slope and
(x_1,y_1) is a point that falls on the line

1) Determine the slope (m)


m=(\displaystyle y_2-y_1)/(\displaystyle x_2-x_1) where two given points are
(x_1,y_1) and
(x_2,y_2)

Plug in the given points (-4, 7) and (5, 3):


m=(\displaystyle 3-7)/(\displaystyle 5-(-4))\\\\m=(\displaystyle 3-7)/(\displaystyle 5+4)\\\\m=(\displaystyle -4)/(\displaystyle 9)

Therefore, the slope of the line is
-(\displaystyle 4)/(\displaystyle 9). Plug this into
y-y_1=m(x-x_1) as
m:


y-y_1=-(\displaystyle 4)/(\displaystyle 9)(x-x_1)

2) Plug a point into
y-y_1=-(\displaystyle 4)/(\displaystyle 9)(x-x_1)


y-y_1=-(\displaystyle 4)/(\displaystyle 9)(x-x_1)

Because we're given two points, there are two ways we can write this equation:


y-y_1=-(\displaystyle 4)/(\displaystyle 9)(x-x_1)\\\\y-7=-(\displaystyle 4)/(\displaystyle 9)(x-(-4))\\\\y-7=-(\displaystyle 4)/(\displaystyle 9)(x+4)

OR


y-3=-(\displaystyle 4)/(\displaystyle 9)(x-5)

I hope this helps!

User Tejeshree
by
7.9k points