Answer:
g = 0.0114 m/s²
Step-by-step explanation:
The value of acceleration due to gravity on the surface of the moon can be given by the following formula:
![g = (Gm)/(r^2)](https://img.qammunity.org/2022/formulas/physics/high-school/vnumyknwjur9jxabawt6x02z0itlv75j0x.png)
where,
g = acceleration due to gravity on the surface of moon = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m = mass of moon = 4.2 x 10¹⁶ kg
r = radius of moon = 1.57 x 10⁴ m
Therefore,
![g= ((6.67\ x\ 10^(-11)\ N.m^2/kg^2)(4.2\ x\ 10^(16)\ kg))/((1.57\ x\ 10^4\ m)^2)](https://img.qammunity.org/2022/formulas/physics/college/sav4bq3jmkrm4r9mswgwgx9h5afjjct02k.png)
g = 0.0114 m/s²