Answer:
0.999999
Explanation:
Given that :
Probability of CD being defective, p = 0.1
q = 1 - p = 1 - 0.1 = 0.9
Total number of CD's = number of trials = 80
Probability, that no more than 35 CD's are defective ;
The question satisfied the requirements for a binomial probability problem ;
Recall :
P(x = x) = nCx * p^x * q^(n-x)
Hence,
P(x ≤ 35) = 80C35 * 0.1^35 * 0.9^(45)
Using calculator to save computation time :
P(x ≤ 35) = 0.999999