Answer:
The right answer is "
".
Step-by-step explanation:
As the outer spherical shell is conducting, so there is no electric field in side from
⇒
.
So the electric potential at all points inside the conducting shell that from
⇒
and will be similar as well as equivalent to the potential on the outer surface of the shell that will be:
⇒
![v=(KQ)/(r_b_2)](https://img.qammunity.org/2022/formulas/physics/college/cyks66e1q5d2hx3zhn1y7zf4awh8qjsx5k.png)
Thus the above is the right solution.