Question

The initial population of a town is 4200​, and it grows with a doubling time of 10 years. What will the population be in 8 ​years?

Answer 1

The population in 8 years will be of 7313.

Explanation:

Population of a town:

The population of a town, after t years, with a doubling time of n years, is given by:

`P(t) = P(0)(2)^{(t)/(n)}`

The initial population of a town is 4200​, and it grows with a doubling time of 10 years.

This means that
`P(0) = 4200, n = 10`

So

`P(t) = 4200(2)^{(t)/(10)}`

What will the population be in 8 ​years?

This is P(8). So

`P(8) = 4200(2)^{(8)/(10)} = 4200(2)^(0.8) = 7313`

The population in 8 years will be of 7313.