Question

What is the distance between the points (5, 7) times

and (-3, 4) on the coordinate
plane?

Answer 1

Answer:

Option B 8.54\ units8.54 units

Explanation:

we know that

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

Let

`\begin{gathered}A(5,7)\\E(-3.4)\end{gathered}`

substitute the values

`dAB=\sqrt{(4-7)^(2)+(-3-5)^(2)}`

`dAB=\sqrt{(-3^(2)+(-8)^(2)}`

`dAB=√(73)=8.54\ units`