Question

An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magnitude of the velocity?

Answer 1

`v=10^5\ m/s`

Step-by-step explanation:

Given that,

Magnetic force acting on an electron,
`F=12.8* 10^(-19)\ N`

The magnitude of the magnetic field,
`B=8* 10^(-5)\ T`

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

`F=qvB`

Where

v is the velocity

So,

`v=(F)/(qB)\\\\v=(12.8* 10^(-19))/(1.6* 10^(-19)* 8* 10^(-5))\\\\v=10^5\ m/s`

So, the magnitude of velocity is
`10^5\ m/s`.