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1 vote
The mean of a certain set of measurements is 27 with a standard deviation of 14. The distribution of the

data from which the sample was drawn is mound-shaped. The proportion of measurements that is less

than 13 is


Less than at least 3

4

.
Exactly 16%.

At least 16%.

At most 16%.

User Sir Ksilem
by
2.9k points

1 Answer

1 vote

Answer:

Exactly 16%.

Explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the z-score of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of a certain set of measurements is 27 with a standard deviation of 14.

This means that
\mu = 27, \sigma = 14

The proportion of measurements that is less than 13 is

This is the p-value of Z when X = 13, so:


Z = (X - \mu)/(\sigma)


Z = (13 - 27)/(14)


Z = -1


Z = -1 has a p-value of 0.16, and thus, the probability is: Exactly 16%.

User Shawn Patrick Rice
by
3.5k points