Answer:
The value of x is
![(7√(6))/(2)](https://img.qammunity.org/2022/formulas/mathematics/college/r0f30i8obbx45zljmist4zvr8yjzr07whv.png)
Solution given:
AB=7
BD=x
<BAC=60°
<DBC=45°
In right angled triangle ABC
Tan 60°=opposite/adjacent
Tan 60°=BC/AB
Substitute value
=
![(BC)/(7)](https://img.qammunity.org/2022/formulas/mathematics/high-school/j0nhqk3o6x6xxzatnz7zjcz151s9i4m7us.png)
BC=
![7√(3)](https://img.qammunity.org/2022/formulas/mathematics/college/hiyce54rpnecjupsgpl0l68a64jbg8021d.png)
again
In right angled triangle BCD
Using Cos angle
Cos 45=adjacent/hypotenuse
Cos45°=BD/BC
Substituting value
![(√(2))/(2)=(x)/(7√(3))](https://img.qammunity.org/2022/formulas/mathematics/college/rizr4m864wuaz0cb4seyvracjhjznp3u19.png)
Doing criss cross multiplication
![(√(2))/(2)*7√(3)=x](https://img.qammunity.org/2022/formulas/mathematics/college/i30yzzf7zd4hz4ralg0ewaiy32984uoqxc.png)
x=
![(7√(6))/(2)](https://img.qammunity.org/2022/formulas/mathematics/college/r0f30i8obbx45zljmist4zvr8yjzr07whv.png)