Question

Find the magnetic force experienced by a proton moving with the speed of 4x10^5 m/s in the magnetic field B of magnetic 7x10^-5 T.

A- Fmagnetic = 24.8x10^-19 N

B- Fmagnetic = 34.8x10^-19 N

C- Fmagnetic = 44.8x10^-19 N

D- Fmagnetic = 54.8x10^-19 N

Answer 1

F = q v B where B is the component of the field perpendicular to v.

F = 1.6E-19 * 4E5 * 7E-5 = 4.48* 10^-18 N = 44.8 * E-19 N