Question

In an experiment 25.0 mL of 0.100 M KI was diluted to 50.0 mL. Calculate the molarity of the diluted solution

Answer 1

The molarity is "0.050 M".

Step-by-step explanation:

The given values are:

M1 = 0.100 M

M2 = ?

V1 = 25.0 mL

V2 = 50.0 mL

As we know,

⇒
`M1* V1=M2* V2`

Or,

⇒
`M2=(M1* V1)/(V2)`

By putting the values, we get

`=(0.100* 25)/(50)`

`=(2.5)/(50)`

`=0.05 \ M`