Answer:
100% of children will have a double heterozygous genotype (EeWw)
Step-by-step explanation:
A homo-zygous individual is an individual that has two dominant alleles or two recessive alleles for a given gene/locus. A dihybrid cross, also known as Mendelian dihybrid cross, refers to a type of cross in which both parents differ in two observed phenotypic traits which are controlled by two distinct non-linked genes. When both parents are inversely homo-zygous for both genes as in this case (i.e., one parent is homo-zygous dominant for the first gene and homo-zygous recessive for the second gene, while the other parent is homo-zygous recessive for the first gene and homo-zygous dominant for the other), all the F1 will be heterozygous, i.e., all F1 individuals will have the EeWw genotype because each parent can produce only one type of gamete (either Ew or eW). If both genes are subject to complete dominance, then the expected phenotypic ratio of the F2 obtained by crossing double heterozygous individuals will be 9:3:3:1, i.e., 9/16 individuals will have the dominant phenotype for both traits (in this case E_W_ genotype), 3/16 individuals will have the dominant phenotype for the first trait (in this case, dominant earlobe E_ww genotype), 3/16 individuals will have the dominant phenotype for the second trait (in this case, dominant hairline eeW_ genotype), and 1/16 will have the recessive phenotype for both traits (in this case, double recessive eeww genotype).