Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long

Answer 1

Complete Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail

Answer:

`F=2*10^(4)N`

Step-by-step explanation:

From the question we are told that:

Mass
`m=0.500kg`

Initial Velocity
`V=15.0m/s`

Distance
`x=2.80mm=>0.00280m`

Diameter
`d=2.50mm=>0.00250m`

Length
`l=6.00cm=>0.6m`

Generally the equation for Force is mathematically given by

`F=(mv^2)/(2d)`

`F=(0.500*15^2)/(2.80*10^(-3))`

`F=2*10^(4)N`