Question

What is the specific rotation of 13g of a molecule dissolved in 10 mL of solvent that gives an observed rotation of 23 degrees in a sample tube of 10 cm.

Answer 1

`\alpha=17.7`

Step-by-step explanation:

From the question we are told that:

Mass
`m=13g`

Volume
`V=10mL`

Angle
`\theta=23`

Sample Tube=10cm

Generally the equation for concentration is mathematically given by

`C=m/v`

`C=(13)/(10)\\C=1.3g/mL`

Therefore the Specific Rotation

`\alpha=frac{\theta }{m*l}`

`\alpha=frac{23 }{1.3*1.0}`

`\alpha=17.7`