Answer:
![-(5)/(2) x^(3) +(17)/(8) x^(2) -15](https://img.qammunity.org/2022/formulas/mathematics/high-school/4dwrubva6etbmhwalfeofltqylfc8k0cy1.png)
Explanation:
First combine like terms so for numbers with x^3 you have one:
-
![(5)/(2) x^(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1kf1qf8ayzjl6cy88aim8gurcah43cum0a.png)
Then x^ 2
![(9)/(8)x^(2) +x^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/aurd8omwa04hd6uu657g5tgfjse7noe39q.png)
(4/4x^2 is just x^2 because 4/4 is 1)
So
![(17)/(8) x^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3sssheyenb7ooaebbknosofmffmzy65pa0.png)
Then all numbers with x cancel out because
2x+3x-5x is 0.
Then you just have -15.
So put them back together to get what I wrote in the answer.
Hope that helps lmk if I calculated that wrong!