Question

i o n f e h y=x3- 3x2- 9 x + 2 The largest and smallest values ​​of the function [ - 2 ; 4 ]At intervals.

Answer 1

Explanation:

Given the function :

y=x³ - 3x² - 9x + 2. The largest and smallest values ​​of the function at interval [-2, 4]

We substitute x values in the interval (-2 to 4) into the equation and solve for y

At x = - 2

y = (-2)³ - 3(-2)² - 9(-2) + 2 = 0

At x = - 1

y = (-1)³ - 3(-1)² - 9(-1) + 2 = 7

At x = 0

y = (-0)³ - 3(-0)² - 9(-0) + 2 = 2

At x = 1

y = (1)³ - 3(1)² - 9(1) + 2 = - 9

At x = 2

y = (2)³ - 3(2)² - 9(2) + 2 = - 20

At x = 3

y = (3)³ - 3(3)² - 9(3) + 2 = - 25

At x = 4

y = (4)³ - 3(4)² - 9(4) + 2 = - 18

Function is greatest at