Answer:
Explanation:
The given side lengths of the right triangle are;
x² - 1, 2·x and x² + 1
A Pythagorean triple are three numbers, a, b, and c, such that, we have;
a² + b² = c²
From the given side lengths, we have;
We note that (x² + 1) > (x² - 1)
(x² + 1) > 2·x for x > 1
Therefore, with (x² + 1) as the hypotenuse side, we have;
(x² - 1)² + (2·x)² = (x² + 1)²
Therefore, when the x-value is 3, we have;
(3² - 1)² + (2 × 3)² = (3² + 1)²
8² + 6² = 10²
The least is 6² = (2 × 3)², from (2·x)²
Therefore;
The Pythagorean triple is 6, 8, 10
The order of the triple is (2·x), (x² - 1), (x² + 1)
2) The x-value for the triple, (8, 15, 17), is obtained as follows;
The least, 8 = 2·x
∴ x = 8/2 = 4
The x-value = 4
3) The Pythagorean triple where the x-value = 5 is therefore;
(2·x), (x² - 1), (x² + 1), where x = 5 gives; (2×5 = 10), (5² - 1 = 24), (5² + 1 = 26)
Therefore, the Pythagorean triple where x = 5 is 10, 24, and 26
4) The x-value for the Pythagorean triple (12, 35, 37) is given by 12 = 2·x
Therefore, x = 12/2 = 6
Therefore, we get;