Question

Train starting from a railway station and moving with a uniform accleration attains a speed of 90km/hr in 10s .Find the accleration

Options
90m/s2
1m/s2
10m/s2
0.1m/s2

Answer 1

a= 2.5m/s²

Step-by-step explanation:

U=0

V=90km/hr

T= 10s

Convert 90km/hr to m/s

1km= 1000m

1hr= 3600s

(60×60)

therefore, 90km/hr = 90000/3600

90km/hr= 25m/s

From Newton First Equation,

V=U + AT

25=0+ A(10)

25= 10A

25/10 =10A/10

A= 2.5m/s²