Question

A jet takes off from an aircraft carrier starting from rest and travels 93 m [fwd] in 1.2 s when being pushed by the catapult. What is its final velocity at takeoff?

Answer 1

The final velocity of the jet at takeoff is 234 m/s.

Step-by-step explanation:

To find the final velocity of the jet at takeoff, we can use the equation:

vf = vi + at

Where vf is the final velocity, vi is the initial velocity (which is 0 in this case), a is the acceleration, and t is the time.

In this case, the jet travels 93 m in 1.2 s and starts from rest, so the initial velocity is 0 and the time is 1.2 s.

Given that information, we can substitute the values into the equation:

vf = 0 + a * 1.2

Now, we need to find the acceleration. We have the distance traveled and the time, so we can use the equation:

d = vit + (1/2)at²

Since the initial velocity is 0, the equation simplifies to:

d = (1/2)at²

Plugging in the given values, we have:

93 = (1/2)a(1.2)²

Solving for a, we get:

a = 195.0 m/s²

Finally, substituting this value of a into the initial equation, we have:

vf = 0 + (195.0)(1.2)

vf = 234 m/s

Therefore, the final velocity of the jet at takeoff is 234 m/s.