Answer:
Region D.
Explanation:
Here we have two inequalities:
y ≤ 1/2x − 3
y < −2/3x + 1
First, we can see that the first inequality has a positive slope and the symbol (≤) so the values of the line itself are solutions, this line is the solid line in the graph.
And we have that:
y ≤ 1/2x − 3
y must be smaller or equal than the solid line, so here we look at the regions below the solid line, which are region D and region C.
Now let's look at the other one:
y < −2/3x + 1
y = (-2/3)*x + 1
is the dashed line in the graph.
And we have:
y < −2/3x + 1
So y is smaller than the values of the line, so we need to look at the region that is below de dashed line.
The regions below the dashed line are region A and region D.
The solution for the system:
y ≤ 1/2x − 3
y < −2/3x + 1
Is the region that is a solution for both inequalities, we can see that the only region that is a solution for both of them is region D.
Then the correct option is region D.