Question

What is the solution to log Subscript 5 Baseline (10 x minus 1) = log Subscript 5 Baseline (9 x + 7)

Answer 1

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`\sf{log_(5)}(\tt{10x-1})=\sf{log_(5)}(\tt{9x+7})\\\\10x-1=9x+7\\\\10x-9x=7+1\\\\\pmb{\green{\underline{\sf{x=\frak{8}}}}}`

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Answer 2

• x = 8

Explanation:

Given:

• log₅ (10x - 1) = log₅ (9x + 7)
• 10x - 1 = 9x + 7
• 10x - 9x = 7 + 1
• x = 8