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The product of 2 consecutive even integers is 16 less than 8 times their sum

User Dan Pritts
by
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1 Answer

5 votes

Answer:

there are two solutions:

x=0

and

x=14

Explanation:

lts suppose the numbers are x and x+2, so:


x(x+2)=8(x+(x+2))-16\\x(x+2)=8(2x+2)-16=16x+16-16=16x\\x^2+2x=16x\\x^2-14x=0\\x(x-14)=0\\x=0,~x=14

User Rkaartikeyan
by
7.3k points

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