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100 g of water are cooled and the enthalpy change is -12,540 J. What is the change in temperature of the water?
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100 g of water are cooled and the enthalpy change is -12,540 J. What is the change in temperature of the water?

User Jiks
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1 Answer

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Answer:

-29.9907

Step-by-step explanation:

c = Q / (mΔT)

You're looking for ΔT, so you would plug in what you already know and get C= -12540/(100 x ΔT)

then you would solve

User Shafeequemat
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