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Use the quadratic formula to solve x^2 + 3^x - 28 = 0

1 Answer

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Explanation:

x^2 + 3x - 28 = 0

x^2 - 7x + 4x - 28 = 0

x(x-7) + 4(x-7) = 0

(x+4)(x-7)= 0

x+4=0 or x-7=0

x= -4 or x=7

User Franklin Diaz
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