Answer:
The program in Java is as follows:
import java.util.*;
public class Main {
public static void removeDuplicate(ArrayList<Integer> list){
ArrayList<Integer> newList = new ArrayList<Integer>();
for (int num : list) {
if (!newList.contains(num)) {
newList.add(num); } }
for (int num : newList) {
System.out.print(num+" "); } }
public static void main(String args[]){
Scanner input = new Scanner(System.in);
ArrayList<Integer> list = new ArrayList<Integer>();
System.out.print("Enter ten integers: ");
for(int i = 0; i<10;i++){
list.add(input.nextInt()); }
System.out.print("The distinct integers are: ");
removeDuplicate(list);
}}
Step-by-step explanation:
This defines the removeDuplicate function
public static void removeDuplicate(ArrayList<Integer> list){
This creates a new array list
ArrayList<Integer> newList = new ArrayList<Integer>();
This iterates through the original list
for (int num : list) {
This checks if the new list contains an item of the original list
if (!newList.contains(num)) {
If no, the item is added to the new list
newList.add(num); } }
This iterates through the new list
for (int num : newList) {
This prints every element of the new list (At this point, the duplicates have been removed)
System.out.print(num+" "); } }
The main (i.e. test case begins here)
public static void main(String args[]){
Scanner input = new Scanner(System.in);
This declares the array list
ArrayList<Integer> list = new ArrayList<Integer>();
This prompts the user for ten integers
System.out.print("Enter ten integers: ");
The following loop gets input for the array list
for(int i = 0; i<10;i++){
list.add(input.nextInt()); }
This prints the output header
System.out.print("The distinct integers are: ");
This calls the function to remove the duplicates
removeDuplicate(list);
}}