Answer:
Mean = 4.2
Mode = 4 and 5
Median = 4
Variance, = 1.956
Standard deviation = 1.395
Explanation:
Given the data :
х = 2, 4, 5, 5, 7, 5, 3, 3, 4, 4
Ordered data : 2, 3, 3, 4, 4, 4, 5, 5, 5, 7
The mean, xbar = Σx / n ; n = sample size = 10
xbar = 42 / 10 = 4.2
The mode : 4 and 5 (most frequently occurring values) (3 frequency each) = BIMODAL
The median = 1/2(n+1)th term
Median = 1/2(11)th term = 5.5 th term
Median = (5th + 6th term) /2 = (4 + 4) / 2 = 4
Variance , s² = Σ(x - xbar)²/(n-1)
Using a calculator :
Variance, s² = 1.956
Standard deviation, s = √variance = √s² = √1.956 = 1.395