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45 votes
45 votes
If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) when n = 5​

User Hassan Raza
by
2.8k points

1 Answer

12 votes
12 votes

Answer:

67

Explanation:

d(n) = 4n + 2

= 4(5) + 2

=22

t(d(n)) = 3(22) + 1

= 67

User Larry Shatzer
by
3.0k points
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