Question

Can anyone please explain this?

Find the equation of locus of a point A(-3,2) and B(0,4).....

what is locus actually?​

Answer 1

Solution given:

Let there be a point P(x, y) equidistant from

A(-3, 2) and B(0,4),

so PA = PB,

`√((x+3)²+(y-2)²)=√((x-0)²+(y-4)²)`

squaring both side

`(√((x+3)²+(y-2)²))^(2)=(√((x-0)²+(y-4)²))²`

x²+6x+9+y²-4y+4=x²+y²-8y+16

x²+6x+y²-4y-x²-y²+8y=16-4-9

6x-4y+8y=3

6x-4y=3 is a required locus

Actually:

A locus is a curve or other figure formed by all the points satisfying a particular equation of the relation between coordinates, or by a point, line, or surface moving according to mathematically defined conditions.