Answer:
An input size of N = 128 makes the algorithm run for 14 milliseconds
Step-by-step explanation:
O(log2N)
This means that the running time for an algorithm of length N is given by:

In which C is a constant.
Runs for 10 milliseconds when the input size (N) is 32.
This means that

So


Since

Then



Thus:

What input size makes the algorithm run for 14 milliseconds
N for which
. So





An input size of N = 128 makes the algorithm run for 14 milliseconds