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Express the trigonometric ratios sinA in term of cosA​

User P H
by
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1 Answer

5 votes

Answer:

sinA = ±
√(1-cos^2A)

Explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract cos²A from both sides )

sin²A = 1 - cos²A ( take the square root of both sides )

sinA = ±
√(1-cos^2A)

User Maghfirzakir
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3.5k points