Answer:
C₆H₁₈O₉
Step-by-step explanation:
First we calculate the molar mass of the compound represented by the empirical formula:
- Molar Mass = (Molar mass of C) * 2 + (Molar Mass of H) * 4 + (Molar Mass of O) * 3
- Molar Mass = 12 * 2 + 1 * 4 + 16 * 3 = 76 g/mol
Then we divide the given formula mass by the calculated molar mass:
Thus we multiply by 3 the subscripts in the empirical formula:
- The molecular formula is C₆H₁₈O₉