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15 votes
15 votes
HELP IN ONE HOUR AND I GIVE U THE BRIANLIEST

HELP IN ONE HOUR AND I GIVE U THE BRIANLIEST-example-1
User Venkatesh K
by
2.5k points

2 Answers

21 votes
21 votes

First of all we need to calculate the area of the floor and then we will find the pressure using the formula for pressure...


\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

Area of floor

  • Length = 1.6 meter
  • Breadth = 2.3 meter


\sf \: area = length * breadth


\sf \: area = 1.6 * 2.3


\sf \: area = 3.68 \: {m}^(2)


\purple{ \rule{300pt}{3pt}}

Finding force ↯

  • Pressure = 200 N/m²
  • Area = 3.68 m²


\tt \: pressure = (force)/(area)


\tt \: 200 = (force)/(3.68)


\tt \: force = 200 * 3.68


\tt \: force = 736 \: newton

Thus, The maximum force is 736 Newton...~

User Eddie Jaoude
by
2.8k points
16 votes
16 votes

Calculate the area of the floor:

Area = 1.6 x 2.3 = 3.68 square meters

Using the given formula: Pressure = force/area

200 = force / 3.68

Solve for force by multiplying both sides by 3.68

Force = 200 x 3.68

Force = 736 N/m^2

Correct to the nearest 5N/m^2 = 735 N/m^2

User Cynda
by
3.0k points