Answer:
Explanation:
|3x-9|≤15
-15≤3x-9≤15
-15+9≤3x≤15+9
-6≤3x≤24
-2≤x≤8
x∈[-2,8]
|2x-3|≥5
2x-3≤-5
2x≤-2
x≤-1
and
2x-3≥5
2x≥8
x≥4
solution is x∈[-2,-1]∪[4,8]
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