Question

A 0.390 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 75.0 pC charge on its surface. What is the potential (in V) near its surface

Answer 1

V = 346.15 Volts

Step-by-step explanation:

Given that,

Diameter of the sphere, d = 0.390 cm

Radius, r = 0.195 cm

Charge,
`q=75\ pC =75* 10^(12)\ C`

The electric potential near its surface is given by :

`V=(kq)/(r)\\\\V=(9* 10^9* 75* 10^(-12))/(0.195* 10^(-2))\\\\V=346.15\ V`

So, the potential near its surface is equal to 346.15 V.