Question

What is the concentration , in grams per liter , of a solution containing 6 mEq of calcium chloride ( CaCl2 ) per milliliter ? ( Ca = 40 , Cl = 35.5 , H = 1 , 0 = 16 )?

Answer 1

333g/L

Step-by-step explanation:

The moles of CaCl2 in 6mEq are:

6mEq * (1mmol / 2mEq) = 3mmol CaCl2.

2Eq / mol because the charge of Ca is 2+

The mass is:

3mmol CaCl2 * (111mg/mmol) = 333mg = 0.333g

Molar mass: 2*35.5g/mol + 40g/mol = 111g/mol = 111mg/mmol

The liters are:

1mL * (1L / 1000mL) = 1x10⁻³L

The concentration in grams per liter is:

0.333g / 1x10⁻³L = 333g/L